IT, Programming, & Web Development › Forums › CS50’s Introduction to Computer Science by Harvard University on Edx › Week 6: Python › CS105: Introduction to Python by Saylor Academy › Unit 4: Data Structures I – Lists and Strings › List slicing in Python: How new lists are created and stored in memory
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August 6, 2024 at 1:04 pm #3189
Source: Created taking help of AI tool
Yes, when you use slicing on a list in Python, a new list is created containing the elements specified by the slice. This new list occupies a different memory space than the original list.
Explanation of Slicing
Slicing a list in Python creates a new list containing the elements specified by the slice indices. The original list remains unchanged, and the new list is a separate object in memory.
Example and Explanation
list = ['a', 'b', 'c', 'd'] print(list[1:-1]) # Outputs: ['b', 'c']
In this example:
–list[1:-1]
creates a new list starting from index1
up to (but not including) the second-to-last element of the original list.
– The resulting new list is['b', 'c']
.
– This new list is stored in a different memory location from the original list.Memory and New List Creation
When you perform slicing:
1. A new list object is created.
2. The elements specified by the slice are copied into this new list.
3. The original list remains unchanged.You can verify that the new list is a different object by comparing their memory addresses using the
id()
function:list = ['a', 'b', 'c', 'd'] new_list = list[1:-1] print(new_list) # Outputs: ['b', 'c'] print(id(list)) # Memory address of the original list print(id(new_list)) # Memory address of the new list
The
id()
function will show different addresses forlist
andnew_list
, confirming that they are distinct objects in memory.Summary
- Slicing a list creates a new list with the specified elements.
- The new list occupies a different memory space from the original list.
- The
print
function will output the contents of the new list when you slice it, notNone
, because slicing returns a new list object, notNone
.
Example Code Demonstrating Memory Addresses
list = ['a', 'b', 'c', 'd'] new_list = list[1:-1] print("Original list:", list) print("Sliced list:", new_list) print("Memory address of the original list:", id(list)) print("Memory address of the new sliced list:", id(new_list))
Output:
Original list: ['a', 'b', 'c', 'd'] Sliced list: ['b', 'c'] Memory address of the original list: 140093642714048 Memory address of the new sliced list: 140093642715200
This demonstrates that the original list and the new sliced list are stored at different memory locations, confirming that slicing creates a new list.
Source: Google, https://developers.google.com/edu/python/lists#list-methods
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