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IT, Programming, & Web Development › Forums › CS50’s Introduction to Computer Science by Harvard University on Edx › Week 1: [C] – Data Types, Operators, Conditional Statements, Loops, and Command Line › Error: format specifies type ‘char’ but the argument has type ‘string’
Tagged: char type, correct format code, get_string(), return value, scanf, storing return value, string type
This is the code written:
#include <stdio.h>
#include <cs50.h>
int main(void)
{
string name = get_string ("what is your name\n");
scanf("%s", &name);
printf("%s",name);
}
On typing help50 make hello command, I get this suggestion:
format specifies type 'char *' but the argument has type 'string *' (aka 'char **') [-Werror,-Wformat]
scanf("%s", &name);
~~ ^~~~~
Be sure to use the correct format code (e.g., %i for integers, %f for floating-point values, %s for strings, etc.) in your format string on line 6 of hello.c. ~/pset1/hello/ $
Do I need to remove string type and instead use char type. If so, why?
#include <stdio.h>
#include <cs50.h>
int main (void)
{
int number;
scanf ("enter a number %i", &number);
printf ("the number is %i", number);
}
Here is the result as I enter 44:
~/pset1/ $ ./Mario 44 the number is 0~/pset1/ $
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