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IT, Programming, & Web Development › Forums › CS50’s Introduction to Computer Science by Harvard University on Edx › Week 1: [C] – Data Types, Operators, Conditional Statements, Loops, and Command Line › Error: format specifies type ‘char’ but the argument has type ‘string’
Tagged: C programming language, char type, correct format code, format string, get_string(), scanf, string type, types in c
This is the code written:
#include<stdio.h> #include<cs50.h> int main(void) { string name = get_string ("what is your name\n"); scanf("%s", &name); printf("%s",name); }
On typing help50 make hello command, I get this suggestion:
hello.c:6:17: error: format specifies type 'char *' but the argument has type 'string *' (aka 'char **') [-Werror,-Wformat] scanf("%s", &name); ~~ ^~~~~ Be sure to use the correct format code (e.g., %i for integers, %f for floating-point values, %s for strings, etc.) in your format string on line 6 of hello.c. ~/pset1/hello/ $
Do I need to remove string type and instead use char type. If so, why?
#include #include int main (void) { int number; scanf ("enter a number %i", &number); printf ("the number is %i", number); } Here is the result as I enter 44
~/pset1/ $ ./Mario 44 the number is 0~/pset1/ $
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https://cs50.stackexchange.com/questions/41713/error-format-specifies-type-char-but-the-argument-has-type-string[learn_press_profile]