IT, Programming, & Web Development › Forums › CS50’s Introduction to Computer Science by Harvard University on Edx › Week 2: [Arrays] – Functions, Variable and Scope, Debugging, Arrays, and Command Line Arguments › Char type while counting number of words in Readability project
Tagged: char type
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December 25, 2021 at 9:07 am #124::
#include #include #include int main(void) { string enterword = get_string("input: "); int t = strlen(enterword); printf("%i\n", t); int counter = 0; for(int i = 0; i<= t; i++) { if (enterword == '.'|| enterword == '!' || enterword == '?'){ counter = counter + 1;} } printf("number of lines %i\n",counter); int wordcounter = 0; for (int i = 0; i<= t; i++) { if (enterword == ' ' || enterword == '.'){ wordcounter = wordcounter + 1; } } printf("total words %i\n", wordcounter); }
The above program fails to calculate correctly no. of words. The problem is that char type can take only one character.
int wordcounter = 0; for (int i = 0; i<= t; i++) { if (enterword == ' ' || enterword == '.'){ wordcounter = wordcounter + 1; } } printf("total words %i\n", wordcounter);
I cannot have enterword == ‘. ‘; that is, one space after. to count correctly number of words when before full stop and a new line starts with a space after that full stop. Seeking help how to approach in such scenario.
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https://edstem.org/us/courses/176/discussion/976408?comment=2210979[learn_press_profile]
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